% vim: ft=tex \section{The Stabilizer Formalism} The stabilizer formalism was originally introduced by Gottesman\cite{gottesman1997} for quantum error correction and is a useful tool to encode quantum information such that it is protected against noise. The prominent Shor code \cite{shor1995} is an example of a stabilizer code (although it was discovered before the stabilizer formalism was discovered), as are the 3-qbit bit-flip and phase-flip codes. It was only later that Gottesman and Knill discovered that stabilizer states can be simulated in polynomial time on a classical machine \cite{gottesman2008}. This performance has since been improved to $n\log(n)$ time on average \cite{andersbriegel2005}. \subsection{Stabilizers and Stabilizer States} \subsubsection{Local Pauli Group and Multilocal Pauli Group} \begin{definition} \begin{equation} P := \{\pm 1, \pm i\} \cdot \{I, X, Y, Z\} \end{equation} Is called the Pauli group. \end{definition} The group property of $P$ can be verified easily. Note that the elements of $P$ either commute or anticommute. \begin{definition} For $n$ qbits \begin{equation} P_n := \{\bigotimes\limits_{i=0}^{n-1} p_i | p_i \in P\} \end{equation} is called the multilocal Pauli group on $n$ qbits. \end{definition} The group property of $P_n$ follows directly from its definition via the tensor product as do the (anti-)commutator relationships. %Further are $p \in P_n$ hermitian and have the eigenvalues $\pm 1$ for %$p \neq \pm I$, $+1$ for $p = I$ and $-1$ for $p = -I$. \subsubsection{Stabilizers} \begin{definition} \label{def:stabilizer} An abelian subgroup $S = \{S^{(0)}, ..., S^{(N)}\}$ of $P_n$ is called a set of stabilizers iff \begin{enumerate} \item{$\forall i,j = 1, ..., N$ $[S^{(i)}, S^{(j)}] = 0$ $S^{(i)}$ and $S^{(j)}$ commute} \item{$-I \notin S$} \end{enumerate} \end{definition} \begin{lemma} If $S$ is a set of stabilizers, the following statements are follow directly \begin{enumerate} \item{$\pm iI \notin S$} \item{$(S^{(i)})^2 = I$ for all $i$} \item{$S^{(i)}$ are hermitian for all $i$} \end{enumerate} \end{lemma} \begin{proof} \begin{enumerate} \item{$(iI)^2 = (-iI)^2 = -I$. Which contradicts the definition of $S$.} \item{From the definition of $S$ ($G_n$ respectively) follows that any $S^{(i)} \in S$ has the form $\pm i^l (\bigotimes\limits_{j=0}^{n-1} \tilde{p}_j)$ where $\tilde{p}_j \in \{X, Y, Z, I\}$ and $l \in \{0, 1\}$. As $(\bigotimes\limits_{j=0}^{n-1} \tilde{p}_j)$ is hermitian $(S^{(i)})^2$ is either $+I$ or $-I$. As $-I \notin S$ $(S^{(i)})^2 = I$ follows directly. } \item{Following the argumentation above $(S^{(i)})^2 = -I \Leftrightarrow l=1$ therefore $(S^{(i)})^2 = -I \Leftrightarrow (S^{(i)})^\dagger \neq (S^{(i)})$.} \end{enumerate} \end{proof} As considering all elements of a group can be unpractical for some calculations the generators of a group are introduced. It is usually enough to discuss the generator's properties to understand the properties of the group. \begin{definition} For a finite group $G$ and some $m \in \mathbb{N}$ one denotes the generators of G $$ \langle g_1, ..., g_m \rangle \equiv \langle g_i \rangle_{i=1,...,m}$$ where $g_i \in G$, every element in $G$ can be written as a product of the $g_i$ and $m$ is the smallest integer for which these statements hold. \end{definition} In the following discussions $\langle S^{(i)} \rangle_{i=0, ..., n-1}$ will be used as the properties of a set of stabilizers that are used in the discussions can be studied using only its generators. \subsubsection{Stabilizer States} One important basic property of quantum mechanics is that hermitian operators have real eigenvalues and eigenspaces associated with these eigenvalues. Finding these eigenvalues and eigenvectors is what one calls solving a quantum mechanical system. One of the most fundamental insights of quantum mechanics is that operators that commute have a common set of eigenvectors, i.e. they can be diagonalized simultaneously. This motivates and justifies the following definition \begin{definition} For a set of stabilizers $S$ the vector space \begin{equation} V_S := \{\ket{\psi} | S^{(i)}\ket{\psi} = +1\ket{\psi} \forall S^{(i)} \in S\} \end{equation} is called the space of stabilizer states associated with $S$ and one says $\ket{\psi}$ is stabilized by $S$. \end{definition} It is clear that it is sufficient to show the stabilization property for the generators of $S$, as all the generators forming an element in $S$ can be absorbed into $\ket{\psi}$. The dimension of $V_S$ is not immediately clear. One can however show that for a set of stabilizers $\langle S^{(i)} \rangle_{i=1, ..., n-m}$ the dimension $dim V_S = 2^m$ \cite[Chapter 10.5]{nielsen_chuang_2010}. This yields the following important result: \begin{theorem} For a $n$ qbit system and a set $S = \langle S^{(i)} \rangle_{i=1, ..., n}$ the stabilizer space $V_S$ has $dim V_S = 1$, in particular there exists an up to a trivial phase unique state $\ket{\psi}$ that is stabilized by $S$. Without proof. \end{theorem} In the following discussions for $n$ qbits a set $S = \langle S^{(i)} \rangle_{i=1,...,n}$ of $n$ independent stabilizers will be assumed. \subsubsection{Dynamics of Stabilizer States} Consider a $n$ qbit state $\ket{\psi}$ that is the $+1$ eigenstate of $S = \langle S^{(i)} \rangle_{i=1,...,n}$ and a unitary transformation $U$ that describes the dynamics of the system, i.e. \begin{equation} \ket{\psi'} = U \ket{\psi} \end{equation} It is clear that in general $\ket{\psi'}$ will not be stabilized by $S$ anymore. There are however some statements that can still be made: \begin{equation} \begin{aligned} \ket{\psi'} &= U \ket{\psi} \\ &= U S^{(i)} \ket{\psi} \\ &= U S^{(i)} U^\dagger U\ket{\psi} \\ &= U S^{(i)} U^\dagger \ket{\psi'} \\ &= S^{\prime(i)} \ket{\psi'} \\ \end{aligned} \end{equation} Note that in \ref{def:stabilizer} it has been demanded that stabilizers are a subgroup of the multilocal Pauli operators. This does not hold true for an arbitrary $U$ but there exists a group for which $S'$ will be a set of stabilizers. \begin{definition} For $n$ qbits \begin{equation} C_n := \left\{U \in SU(n) | UpU^\dagger \in P_n \forall p \in P_n\right\} \end{equation} is called the Clifford group. $C_1 =: C_L$ is called the local Clifford group. \end{definition} \begin{theorem} \begin{enumerate} \item{$C_L$ can be generated using only $H$ and $S$.} \item{$C_L$ can be generated from $\sqrt{iZ} = \exp(\frac{i\pi}{4}) S^\dagger$ and $\sqrt{-iX} = \frac{1}{\sqrt{2}} \left(\begin{array}{cc} 1 & -i \\ -i & 1 \end{array}\right)$. Also $C_L$ is generated by a product of at most $5$ matrices $\sqrt{iZ}$, $\sqrt{-iX}$. } \item{$C_n$ can be generated using $C_L$ and $CZ$ or $CX$.} \end{enumerate} \end{theorem} \begin{proof} \begin{enumerate} \item{See \cite[Theorem 10.6]{nielsen_chuang_2010}} \item{ One can easily verify that $\sqrt{iZ} \in C_L$ and $\sqrt{-iX} \in C_L$. Further one can show easily that (up to a global phase) $H = \sqrt{iZ} \sqrt{-iX}^3 \sqrt{iZ}$ and $S = \sqrt{iZ}^3$. The length of the product can be seen when explicitly calculating $C_L$. } \item{See \cite[Theorem 10.6]{nielsen_chuang_2010}} \end{enumerate} \end{proof} This is quite an important result: As under a transformation $U \in C_n$ $S'$ is a set of $n$ independent stabilizers and $\ket{\psi'}$ is stabilized by $S'$ one can consider the dynamics of the stabilizers instead of the actual state. This is considerably more efficient as only $n$ stabilizers have to be modified, each being just the tensor product of $n$ Pauli matrices. This has led to the simulation using stabilizer tableaux \cite{gottesman_aaronson2008}. Interestingly also measurements are dynamics covered by the stabilizers. When an observable $g_i \in \{\pm X_i, \pm Y_i \pm Z_i\}$ is measured