some work on the presentation
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@ -561,10 +561,12 @@
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Many Clifford operations cannot be described by the VOP-free graph states.\\
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Example:
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\begin{equation}
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G = \left(\{0, 1\}, \{\}\right)
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%\ket{\bar{G}} &= \ket{+}\\
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%U &= H_0H_1 \\
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%U \ket{\bar{G}} &= \ket{\mbox{0b}00}\\
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\begin{aligned}
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&G = \left(\{0, 1\}, \{\}\right)\\
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&\ket{\bar{G}} = \ket{+}\\
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&U = H_0H_1 \\
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&U \ket{\bar{G}} = \ket{\mbox{0b}00}\\
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\end{aligned}
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\end{equation}
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