just a paragraph
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@ -521,4 +521,20 @@ it is clear that just the vertex operators are changed and the new vertex operat
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\end{aligned}
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\end{aligned}
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\end{equation}
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\end{equation}
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The action of a $CZ$ gate on the state $(V, E, O)$ is less trivial
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The action of a $CZ$ gate on the state $(V, E, O)$ is in most cases less trivial.
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Let $i \neq j$ be two qbits, now consider the action of $CZ_{i,j}$ on $(V, E, O)$.
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The following discussion closely follows \cite{andersbriegel2005} and is analogous
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to the implementation.
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\textbf{Case 1:}
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Both $o_i$ and $o_j$ commute with $CZ_{i,j}$. This is the case for exactly
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four vertex operators: $\mathcal{Z} = \left\{I, Z, S, S^\dagger\right\}$.
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In this case the CZ can be pulled past the vertex operators and just the edges
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are changed to $E' = E \Delta \left\{\{i,j\}\right\}$.
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\textbf{Case 2:}
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At least one vertex operator does not commute with $CZ_{i,j}$.
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\textbf{Sub-Case 2.1}
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Both
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