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+% vim: ft=tex
+\section{Introduction to Binary Quantum Computing}
+
+\subsection{Single Qbits}
+
+A qbit is a two-level quantum mechanical system $ \{\ket{\uparrow} \equiv \ket{1}, \ket{\downarrow} \equiv \ket{0}\} $
+with $\braket{\uparrow}{\downarrow} = 0$. One can associate 
+$\ket{\uparrow} \equiv \left(\begin{array}{c} 0 \\ 1\end{array} \right)$ and 
+$\ket{\downarrow} \equiv \left(\begin{array}{c} 1 \\ 0 \end{array} \right)$ which
+is helpful in the following discussion.
+
+A gate operating on a qbit is a unitary operator $G \in U(2)$. One can show that
+$\forall G \in U(2)$ $G$ can be expressed as a product of unitary generator matrices,
+common choices for the generators are $ X, H, R_{\phi}$ and $Z, H, R_{\phi}$ with 
+\label{ref:singleqbitgates}
+
+$$X := \left(\begin{array}{cc} 0 & 1 \\ 1 & 0\end{array}\right) $$
+$$Z := \left(\begin{array}{cc} 1 & 0 \\ 0 & -1\end{array}\right) $$
+$$H := \frac{1}{\sqrt{2}}\left(\begin{array}{cc} 1 & 1 \\ 1 & -1\end{array}\right) $$
+$$R_{\phi} := \left(\begin{array}{cc} 1 & 0 \\ 0 & \exp(i\phi)\end{array}\right) $$
+
+\subsection{$N$ Qbit Systems}
+\label{ref:nqbitsystems}
+
+A system of $N$ identical qbits is described by the kronecker product of the
+single qbit states. A nice definition for this product is:
+
+\begin{definition}
+    
+Let $M$, $N$ be complex matrices, $M = \left(\begin{array}{cc} M_1 & M_2 \\ M_3 & M_4 \end{array}\right)$
+. Then the kronecker product is defined as 
+    
+$$M \otimes N = \left(\begin{array}{cc} M_1 \otimes N & M_2 \otimes N \\ M_3 \otimes N & M_4 \otimes N \end{array}\right)$$
+
+Where for any $c \in \mathbb{C}$ $ c \otimes N := cN$.
+\end{definition}
+
+
+\begin{postulate}
+A $N$ qbit quantum mechanical state is the kronecker product of the $N$ single qbit 
+state. 
+\end{postulate}
+
+Let $\ket{0}_s := \left(\begin{array}{c} 1 \\ 0 \end{array} \right)$ and $\ket{1}_s := \left(\begin{array}{c} 0 \\ 1 \end{array} \right)$
+be the basis of the one-qbit systems. Then two-qbit states are defined as
+
+$$ \ket{0} := \ket{0b00} := \ket{0}_s \otimes \ket{0}_s :=  \left(\begin{array}{c} 1 \\ 0 \\ 0 \\ 0 \end{array} \right)$$
+$$ \ket{1} := \ket{0b01} := \ket{0}_s \otimes \ket{1}_s :=  \left(\begin{array}{c} 0 \\ 1 \\ 0 \\ 0 \end{array} \right)$$
+$$ \ket{2} := \ket{0b10} := \ket{1}_s \otimes \ket{0}_s :=  \left(\begin{array}{c} 0 \\ 0 \\ 1 \\ 0 \end{array} \right)$$
+$$ \ket{3} := \ket{0b11} := \ket{1}_s \otimes \ket{1}_s :=  \left(\begin{array}{c} 0 \\ 0 \\ 0 \\ 1 \end{array} \right)$$
+
+The $N$ qbit basis states can then be constructed in a similar manner. 
+A general $N$ qbit state can then be written as a superposition of the 
+basis states:
+
+$$ \ket{\psi} = \sum\limits_{i = 0}^{2^N - 1} c_i \ket{i} $$
+$$ \sum\limits_{i = 0}^{2^N - 1} |c_i|^2 = 1$$
+
+One can show that the gates in \ref{ref:singleqbitgates} together with an entanglement gate, such as $CX$ or $CZ$ are enough
+to generate an arbitrary $N$ qbit gate.
+
+
+$$ CX(1, 0) = \left(\begin{array}{cccc} 1 & 0 & 0 & 0\\ 0 & 1 & 0 & 0\\ 0 & 0 & 0 & 1\\ 0 & 0 & 1 & 0 \end{array}\right)$$
+$$ CZ(1, 0) = \left(\begin{array}{cccc} 1 & 0 & 0 & 0\\ 0 & 1 & 0 & 0\\ 0 & 0 & 1 & 0\\ 0 & 0 & 0 & -1 \end{array}\right)$$
+
+
+Where $1$ is the act-qbit and $0$ the control-qbit.
+
+\subsection{Measurement}
+
+\begin{postulate}
+
+    Let $\ket{\psi} = \alpha\ket{\phi_1} \otimes \ket{1}_n + \beta\ket{\phi_0} \otimes \ket{0}_n$ be a state
+    where $\ket{1}_n, \ket{0}_n$ denote the $n$-th qbit state and $|\alpha|^2 + |\beta|^2 = 1$. 
+    Then the measurement of the $n$-th qbit will yield $\ket{\phi_1} \otimes \ket{1}_n$ with probability
+    $|\alpha|^2$ and $\ket{\phi_0} \otimes \ket{0}_n$ with probability $|\beta|^2$.
+
+    This is called collapse of the wave function.
+\end{postulate}
+
+Measuring a qbit will also yield a classical result $0$ or $1$ with the respective probabilities.